-16x^2+32x+132=0

Solution for -16x^2+32x+132=0 equation:

-16x^2+32x+132=0

a = -16; b = 32; c = +132;
Δ = b2-4ac
Δ = 322-4·(-16)·132
Δ = 9472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9472}=\sqrt{256*37}=\sqrt{256}*\sqrt{37}=16\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16\sqrt{37}}{2*-16}=\frac{-32-16\sqrt{37}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16\sqrt{37}}{2*-16}=\frac{-32+16\sqrt{37}}{-32}
$